User rating after problem 200

Georg · Post by **Georg** » Mon Mar 31, 2008 6:05 pm

How will the user rating be displayed after problem 200 has been published?

If nothing is changed, having solved 199 out of 200 problems will result in a rating of 100%.
If the floor function will be used instead of the round function, this rating will be 99%.
I want to suggest to use an additional significant digit. Then this rating would be 99.5%.

euler · Post by **euler** » Mon Mar 31, 2008 6:26 pm

It actually ranks on the number of problems solved not the %age genius rating. So 200/200 will be better than 199/200. If ranks are tied after that, it then ranks on the lastsolved time stamp. In other words, if two users have solved 200/200 it then looks at which member's lastsolved timestamp is the oldest, as it means they got to that point quicker than others. That's why the top dogs battle to solve the new problems when they are released, as the first to solve will take the #1 spot.

Tommy137 · Post by **Tommy137** » Mon Mar 31, 2008 6:35 pm

Georg wrote:How will the user rating be displayed after problem 200 has been published?

If nothing is changed, having solved 199 out of 200 problems will result in a rating of 100%.
If the floor function will be used instead of the round function, this rating will be 99%.
I want to suggest to use an additional significant digit. Then this rating would be 99.5%.

That's exactly the same question I asked myself a few days ago

Georg · Post by **Georg** » Mon Mar 31, 2008 6:54 pm

@euler: I see no problem with the ranking. I'm asking for the rating, that is displayed at the problems page or the top 1000 page. Will the users having solved 199 out of 200 problems belong to the 100% club?

euler · Post by **euler** » Mon Mar 31, 2008 11:37 pm

Oh, I understand now. And you know I hadn't thought about that. At the moment it calculates the rating based on round(100*[number solved]/[number of problems]), so you're right, it would round 199/200 to 100%.

Hmm? What do other members think? floor([number solved]/[number of problems]) or 100*round([number solved]/[number of problems],3)?

Tommy137 · Post by **Tommy137** » Tue Apr 01, 2008 12:12 am

below 99%: round(100*[number solved]/[number of problems]) like before
then floor([number solved]/[number of problems])

JohnMorris · Post by **JohnMorris** » Tue Apr 01, 2008 3:00 am

euler wrote:floor([number solved]/[number of problems])

One vote for that one.

hk · Post by hk » Tue Apr 01, 2008 9:49 am

I support that but "number solved" dropping the percentage entirely would be equally good.

ed_r · Post by **ed_r** » Tue Apr 01, 2008 11:19 am

I vote for percentage solved and for that to be floor(solved/total).

rlindley · Post by **rlindley** » Tue Apr 01, 2008 11:23 am

Not that I'll ever get there, but I sure like the ring of 100%-er.

Georg · Post by **Georg** » Sat Jun 28, 2008 10:06 am

Georg wrote:How will the user rating be displayed after problem 200 has been published?

If nothing is changed, having solved 199 out of 200 problems will result in a rating of 100%.
If the floor function will be used instead of the round function, this rating will be 99%.
I want to suggest to use an additional significant digit. Then this rating would be 99.5%.

Nothing was changed.

funktio · Post by **funktio** » Sat Jun 28, 2008 11:15 am

I vote for floor, too.

Looks like ed_r is a 100% genius for the first time now.

ed_r · Post by **ed_r** » Sat Jun 28, 2008 11:27 am

And it'll be a legitimate 100% just as soon as I crack that problem #1 ...

euler · Post by **euler** » Sat Jun 28, 2008 11:45 am

Oops! After all this discussing number 200 arrive and I forgot to make the change. Thanks for the feedback... I went with: floor(100*[number solved]/[number of problems]).

Georg · Post by **Georg** » Sat Jun 28, 2008 12:19 pm

Thanks for fixing it. And now I'm again at 100%.

daniel.is.fischer · Post by **daniel.is.fischer** » Sat Jun 28, 2008 12:30 pm

funktio wrote:I vote for floor, too.

Looks like ed_r is a 100% genius for the first time now.

Nah! He was taking up too much space in the top spots, so we removed him from there by bribing him into the team

ed_r · Post by **ed_r** » Sat Jun 28, 2008 1:18 pm

Oh yeah, the bribe. When exactly do I get my magnum of Margaux '82?

daniel.is.fischer · Post by **daniel.is.fischer** » Sat Jun 28, 2008 1:43 pm

Why, '82 of course, it has to acquire a good age before it's worth drinking

Tommy137 · Post by **Tommy137** » Sat Jun 28, 2008 4:32 pm

Your current rating is 99% genius, having solved 197 out of 200 problems.

It seems you didn't correct the display at the problem page, euler. At the scores page you are only a 98% genius with 197 solved problems

euler · Post by **euler** » Sat Jun 28, 2008 8:02 pm

Thanks for that, Tommy137. Fixed.

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User rating after problem 200

User rating after problem 200

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