PE0765

[henrig]

I would just like to clarify that "certain amount of your gold" means that before each toss, you bet this fixed proportion of gold you have after the previous toss.

[neverforget]

Nowhere is it mentioned the wager must be a fixed proportion. You can pick a different wager before each round, and the amount you pick can depend on the previous rounds' outcomes.

[deWalk]

must bet be an integer?

[neverforget]

must bet be an integer?

You can bet any non-negative real amount you have.

[abcwuhang]

Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

[philiplu]

Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Yeah, the "double your bet" in the problem statement seems ambiguous. I'm not sure if that means winning a bet of b grams means you end up with x+b or x+2b, though I've been assuming it meant x+b.

[neverforget]

Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Not quite. If you have $x$ and wager $b\leq x$ and win, you now have $x-b+2b=x+b$.

[pjt33]

Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Not quite. If you have $x$ and wager $b\leq x$ and win, you now have $x-b+2b=x+b$.

Do you have any evidence to back up this assertion? Because I would note that in the "part I" of this problem (#267) an explicit example is given where you have 1 GBP, bet 0.25 GBP, win, and end up with 1.5 GBP.

[neverforget]

Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Not quite. If you have $x$ and wager $b\leq x$ and win, you now have $x-b+2b=x+b$.

Do you have any evidence to back up this assertion? Because I would note that in the "part I" of this problem (#267) an explicit example is given where you have 1 GBP, bet 0.25 GBP, win, and end up with 1.5 GBP.

I suppose the evidence is that accepted solution uses the standard "double or nothing" interpretation, instead of the one in problem 267.

[philiplu]

Nice find for the language in Problem 267 (View Problem), @pjt33. I'd agree that and Problem 765 (View Problem) clearly have contradictory meanings for "double your bet". As @neverforget says, the interpretation in this new problem must be $x+b$, not $x+2b$, because assuming that let me get the checkmark

Admins, might be nice to clarify the wording in this problem.

[urimend]

Problem 765 (View Problem) has been modified to clarify the meaning of "double your bet".

Thanks for your observation and feedback.

[neverforget]

Problem 765 (View Problem) has been modified to clarify the meaning of "double your bet".

Thanks for your observation and feedback.

Thanks urimend, it is much clearer now!