I am having issues with scaling my solution to 100!
For now, I would like to ask whether my solution for 50! is correct or not.
I found there are <snipped> "families" of product pairs -- each family is where the number of divisors of either element in the pair is the same. E.g., I found <snipped> pairs where either factor has <snipped> divisors; <snipped> pairs each having <snipped> divisors, etc.
C(50!) = <snipped>
The program literally ran for several hours.
In general, how do I find a, b, c, ... such that
<snipped>
Can anyone nudge me towards a Wikipedia or Wolfram article that would get me going?
thank you,
Problem 598
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Comments, questions and clarifications about PE problems.
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hk
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Re: Problem 598
The answer you gave for C(50!) is correct.
I removed possible spoilers of any kind.
I removed possible spoilers of any kind.
War ruins the life and health of untold numbers of innocent children.
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h_anand
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