Project Euler Forum

I would just like to clarify that "certain amount of your gold" means that before each toss, you bet this fixed proportion of gold you have after the previous toss.

Nowhere is it mentioned the wager must be a fixed proportion. You can pick a different wager before each round, and the amount you pick can depend on the previous rounds' outcomes.

must bet be an integer?

deWalk wrote: Sun Sep 19, 2021 7:07 am must bet be an integer?

You can bet any non-negative real amount you have.

Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

abcwuhang wrote: Sun Sep 19, 2021 4:16 pm Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Yeah, the "double your bet" in the problem statement seems ambiguous. I'm not sure if that means winning a bet of b grams means you end up with x+b or x+2b, though I've been assuming it meant x+b.

abcwuhang wrote: Sun Sep 19, 2021 4:16 pm Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Not quite. If you have $x$ and wager $b\leq x$ and win, you now have $x-b+2b=x+b$.

neverforget wrote: Sun Sep 19, 2021 8:08 pm

abcwuhang wrote: Sun Sep 19, 2021 4:16 pm Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Not quite. If you have $x$ and wager $b\leq x$ and win, you now have $x-b+2b=x+b$.

Do you have any evidence to back up this assertion? Because I would note that in the "part I" of this problem (#267) an explicit example is given where you have 1 GBP, bet 0.25 GBP, win, and end up with 1.5 GBP.

pjt33 wrote: Mon Sep 20, 2021 9:18 am

neverforget wrote: Sun Sep 19, 2021 8:08 pm

abcwuhang wrote: Sun Sep 19, 2021 4:16 pm Say I have x gram of gold and I bet b gram (0<=b<=x). If just considering one round, is it correct that I end up with x+2b gram if I win, and end up with x-b if I lose?

Not quite. If you have $x$ and wager $b\leq x$ and win, you now have $x-b+2b=x+b$.

Do you have any evidence to back up this assertion? Because I would note that in the "part I" of this problem (#267) an explicit example is given where you have 1 GBP, bet 0.25 GBP, win, and end up with 1.5 GBP.

I suppose the evidence is that accepted solution uses the standard "double or nothing" interpretation, instead of the one in problem 267.

Nice find for the language in Problem 267 (View Problem), @pjt33. I'd agree that and Problem 765 (View Problem) clearly have contradictory meanings for "double your bet". As @neverforget says, the interpretation in this new problem must be $x+b$, not $x+2b$, because assuming that let me get the checkmark

Admins, might be nice to clarify the wording in this problem.

Problem 765 (View Problem) has been modified to clarify the meaning of "double your bet".

Thanks for your observation and feedback.

urimend wrote: Fri Sep 24, 2021 5:04 am Problem 765 (View Problem) has been modified to clarify the meaning of "double your bet".

Thanks for your observation and feedback.

Thanks urimend, it is much clearer now!