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Problem 032
Posted: Sun Apr 20, 2008 11:44 am
by friol
Hello.
I think I've found the solution to problem 32, but projecteuler.net rejects it.
Problem 32 asks:
"Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital. "
I think these are the products:
[edit]Removed correct solution set[/edit]
and the sum of the products is _____, but it does not seem to be the answer.
What I'm doing wrong?
Thanks
Re: Problem 32
Posted: Sun Apr 20, 2008 11:54 am
by euler
I've edited your post to remove the list, as it is correct. Remember, the word product means the answer you get from multiplying. You might find the hint in the problem statement helpful.

Re: Problem 32
Posted: Sun Apr 20, 2008 11:59 am
by friol
Now I've got it 8-D
Thanks.
Re: Problem 32
Posted: Sun Apr 20, 2008 12:00 pm
by euler
You're welcome, and congrats.
Re: Problem 32
Posted: Fri Oct 17, 2008 2:54 pm
by vzhilyaev
Am I getting it right that multiplicand/multiplier/product should have in total exactly nine digits?
Re: Problem 32
Posted: Fri Oct 17, 2008 3:18 pm
by daniel.is.fischer
Yes.
Problem 32
Posted: Tue Nov 25, 2008 11:55 am
by marco6
can anyone explain me what does "pandigital" mean?
thanks
Re: Problem 32
Posted: Tue Nov 25, 2008 12:10 pm
by Georg
Problem 41 (
View Problem): We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once.
Re: Problem 32
Posted: Tue Nov 25, 2008 6:14 pm
by euler
Good question, marco6. I hadn't realised that a definition was missing from that question. I've added the same definition from problem 41 (thanks, Georg) as an introduction to the problem.
Problem 32 (
View Problem)
Re: Problem 32
Posted: Wed Nov 26, 2008 12:28 pm
by marco6
Thank you for your answer!
Re: Problem 032
Posted: Sat Feb 07, 2009 11:54 pm
by Sunhill
Mods: A very small typo in the last word of the first paragraph - "pandigitial".
Re: Problem 032
Posted: Sun Feb 08, 2009 12:54 am
by daniel.is.fischer
Thanks - fixed.
Re: Problem 032
Posted: Fri Jan 21, 2011 12:43 pm
by masteusz
Hello,
I think that I have found correct solution but ProjectEuler rejects it so I have a question:
For example is 39 x 186 = 7254 and 186 x 39 = 7254 counted as one or two different pandigital identities?
Re: Problem 032
Posted: Fri Jan 21, 2011 2:29 pm
by jaap
One. The problem clearly states:
HINT: Some products can be obtained in more than one way so be sure to only include it once in your sum.
Note that this is even stricter than just swapping the two factors.
Re: Problem 032
Posted: Thu Feb 03, 2011 8:11 am
by masteusz
Thanks, I omitted the word "once" while I was reading

Re: Problem 032
Posted: Sun Feb 27, 2011 4:36 am
by jhughes
Could someone explain to me what this problem is referring to by "identity"? I know it's meaning in other contexts, not this one.
Thanks in advance!
Re: Problem 032
Posted: Sun Feb 27, 2011 6:12 am
by rayfil
When you have an equal sign (=), it means that both sides must be considered identical. Thus, 39 × 186 can be considered an identity of 7254. Similarly 78 x 93, 31 x 234 and 13 x 18 x 31 would also be considered identities of 7254 among many others.
Re: Problem 032
Posted: Tue Jun 14, 2011 6:09 pm
by Spura
Do we have to consider solutions with multiple multiplicands?
X * Y * Z = U
?
Re: Problem 032
Posted: Tue Jun 14, 2011 8:38 pm
by hk
Spura wrote:Do we have to consider solutions with multiple multiplicands?
X * Y * Z = U
?
No
Re: Problem 032
Posted: Tue Jun 14, 2011 8:47 pm
by Molx
Spura wrote:Do we have to consider solutions with multiple multiplicands?
X * Y * Z = U
?
No, only Multiplicand * Multiplier = Product
Problem 32 (
View Problem)