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Problem 093

Posted: Sun Nov 11, 2007 8:16 am
by ssp
Hello. I've suppose it's easy problem, and i solve it, but my algorithm seems wrong:
it can't found equation for {1,2,3,4} set where answer is 22. Can anyone post those equation?
(Problem statement says it exists).

Re: Problem 93 hint

Posted: Sun Nov 11, 2007 12:31 pm
by stijn263
2*(3*4-1) = 22

Re: Problem 093

Posted: Wed Nov 04, 2009 11:08 pm
by LarryBlake
Well, I do get 28 for the example (digits 1, 2, 3, 4). But I also get the wrong overall answer.

Could someone please post another digit combination and its count, so that I can try to figure out where I'm going wrong? Thanks.

Re: Problem 093

Posted: Wed Nov 04, 2009 11:28 pm
by LarryBlake
Does this count:
(6 / 9) * 3 = 2

I wouldn't find that, because I reject 6/9 as not an integer. (Yes, I know I could have rewritten this as (3 * 6) / 9. Maybe it doesn't matter.)

Re: Problem 093

Posted: Wed Nov 04, 2009 11:36 pm
by daniel.is.fischer
Yes, it does count. Intermediate results need not be integers, only the final result must be an integer.

Re: Problem 093

Posted: Thu Nov 05, 2009 12:43 am
by LarryBlake
Okay, thanks. Could you please also post another combination and its count?

Re: Problem 093

Posted: Thu Nov 05, 2009 1:28 pm
by LarryBlake
Anyone?

Re: Problem 093

Posted: Thu Nov 05, 2009 2:52 pm
by zwuupeape
Yeah: 2679 gives 21 consecutive numbers, and 2389 gives 33.

Re: Problem 093

Posted: Thu Nov 05, 2009 3:04 pm
by LarryBlake
Thank you.

Problem 93

Posted: Tue Mar 16, 2010 5:49 am
by bobfin
I have been struggling with problem 93 and think I have solution but my submitted solution is not correct. My method correctly finds that the digit set {1,2,3,4} yields a run of consecutive numbers 1 .. 28. Could anyone confirm the result for the set {4,5,7,8} is a sequence of 26 consecutive numbers. I hope this note is not a spoiler.

Re: Problem 93

Posted: Tue Mar 16, 2010 11:03 am
by Fede
Hi,
my probabilistic algo gives me:
Expand
17
consecutives for [4, 5, 7, 8].

It may not be exactly that but if it's not it should be pretty close.

Re: Problem 93

Posted: Tue Mar 16, 2010 11:11 am
by stijn263
Problem 93 (View Problem)

I also get 17 for {4,5,7,8}. What solution does your program give for {4,5,7,8} --> 18 ?

Re: Problem 093

Posted: Tue Mar 16, 2010 11:19 pm
by bobfin
Thanks for the feedback. I have now located my problem (integer arithmetic) and have successfully completed the problem.

Re: Problem 093

Posted: Sat Sep 11, 2010 7:51 pm
by Tridecagon
Hi, could someone post the equation resulting in 15 for [2,6,7,9]? My algorithm doesn't find it and I can't figure out why.
Thanks!

Re: Problem 093

Posted: Sat Sep 11, 2010 8:34 pm
by harryh
( 7 - ( 9 / 2 ) ) * 6

Re: Problem 093

Posted: Sun Sep 12, 2010 12:33 am
by rayfil
Would the following also be acceptable to you?

(9-6)*(7-2)

Re: Problem 093

Posted: Sun Sep 12, 2010 12:05 pm
by Tridecagon
Thanks for your help, I've found my mistake and solved the problem. :)

Re: Problem 093

Posted: Tue Jan 18, 2011 2:00 am
by GenePeer
zwuupeape wrote:Yeah: 2679 gives 21 consecutive numbers, and 2389 gives 33.
My final solution was correct and I got the same value for 2679 but not for 2389 :? How do you evaluate 15 with [2,3,8,9]?

Re: Problem 093

Posted: Tue Jan 18, 2011 3:13 am
by TripleM
3 * (9 - 8/2)

Re: Problem 093

Posted: Wed Jan 19, 2011 4:31 pm
by GenePeer
Thanks. I got lucky, my program was skipping a few combinations. I fixed the problem though.